mirror of
https://github.com/donnemartin/interactive-coding-challenges
synced 2026-01-03 16:08:02 +00:00
220 lines
6.4 KiB
Python
220 lines
6.4 KiB
Python
{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"This notebook was prepared by [Rishi Rajasekaran](https://github.com/rishihot55). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges)."
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"# Solution Notebook"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Problem: Find all valid combinations of n-pairs of parentheses.\n",
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"\n",
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"* [Constraints](#Constraints)\n",
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"* [Test Cases](#Test-Cases)\n",
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"* [Algorithm](#Algorithm)\n",
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"* [Code](#Code)\n",
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"* [Unit Test](#Unit-Test)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Constraints\n",
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"\n",
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"* Is the input an integer representing the number of pairs?\n",
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" * Yes\n",
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"* Can we assume the inputs are valid?\n",
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" * No\n",
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"* Is the output a list of valid combinations?\n",
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" * Yes\n",
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"* Should the output have duplicates?\n",
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" * No\n",
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"* Can we assume this fits memory?\n",
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" * Yes"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Test Cases\n",
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"\n",
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"<pre>\n",
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"* None -> Exception\n",
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"* Negative -> Exception\n",
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"* 0 -> []\n",
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"* 1 -> ['()']\n",
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"* 2 -> ['(())', '()()']\n",
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"* 3 -> ['((()))', '(()())', '(())()', '()(())', '()()()']\n",
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"</pre>"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"# Algorithm\n",
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"\n",
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"Let `l` and `r` denote the number of left and right parentheses remaining at any given point. \n",
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"The algorithm makes use of the following conditions applied recursively:\n",
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"* Left braces can be inserted any time, as long as we do not exhaust them i.e. `l > 0`.\n",
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"* Right braces can be inserted, as long as the number of right braces remaining is greater than the left braces remaining i.e. `r > l`. Violation of the aforementioned condition produces an unbalanced string of parentheses.\n",
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"* If both left and right braces have been exhausted i.e. `l = 0 and r = 0`, then the resultant string produced is balanced.\n",
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"\n",
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"The algorithm can be rephrased as:\n",
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"* Base case: `l = 0 and r = 0`\n",
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" - Add the string generated to the result set\n",
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"* Case 1: `l > 0`\n",
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" - Add a left parenthesis to the parentheses string.\n",
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" - Recurse (l - 1, r, new_string, result_set)\n",
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"* Case 2: `r > l`\n",
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" - Add a right parenthesis to the parentheses string.\n",
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" - Recurse (l, r - 1, new_string, result_set)\n",
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"\n",
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"Complexity:\n",
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"* Time: `O(4^n/n^(3/2))`, see [Catalan numbers](https://en.wikipedia.org/wiki/Catalan_number#Applications_in_combinatorics) - 1, 1, 2, 5, 14, 42, 132...\n",
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"* Space complexity: `O(n)`, due to the implicit call stack storing a maximum of 2n function calls)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Code"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 1,
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"metadata": {},
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"outputs": [],
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"source": [
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"class Parentheses(object):\n",
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"\n",
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" def find_pair(self, num_pairs):\n",
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" if num_pairs is None:\n",
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" raise TypeError('num_pairs cannot be None')\n",
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" if num_pairs < 0:\n",
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" raise ValueError('num_pairs cannot be < 0')\n",
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" if not num_pairs:\n",
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" return []\n",
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" results = []\n",
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" curr_results = []\n",
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" self._find_pair(num_pairs, num_pairs, curr_results, results)\n",
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" return results\n",
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"\n",
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" def _find_pair(self, nleft, nright, curr_results, results):\n",
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" if nleft == 0 and nright == 0:\n",
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" results.append(''.join(curr_results))\n",
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" else:\n",
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" if nleft >= 0:\n",
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" self._find_pair(nleft-1, nright, curr_results+['('], results)\n",
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" if nright > nleft:\n",
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" self._find_pair(nleft, nright-1, curr_results+[')'], results)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Unit Test"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 2,
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"metadata": {},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"Overwriting test_n_pairs_parentheses.py\n"
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]
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}
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],
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"source": [
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"%%writefile test_n_pairs_parentheses.py\n",
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"import unittest\n",
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"\n",
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"\n",
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"class TestPairParentheses(unittest.TestCase):\n",
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"\n",
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" def test_pair_parentheses(self):\n",
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" parentheses = Parentheses()\n",
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" self.assertRaises(TypeError, parentheses.find_pair, None)\n",
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" self.assertRaises(ValueError, parentheses.find_pair, -1)\n",
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" self.assertEqual(parentheses.find_pair(0), [])\n",
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" self.assertEqual(parentheses.find_pair(1), ['()'])\n",
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" self.assertEqual(parentheses.find_pair(2), ['(())',\n",
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" '()()'])\n",
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" self.assertEqual(parentheses.find_pair(3), ['((()))',\n",
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" '(()())',\n",
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" '(())()',\n",
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" '()(())',\n",
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" '()()()'])\n",
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" print('Success: test_pair_parentheses')\n",
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"\n",
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"\n",
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"def main():\n",
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" test = TestPairParentheses()\n",
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" test.test_pair_parentheses()\n",
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"\n",
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"\n",
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"if __name__ == '__main__':\n",
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" main()"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 3,
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"metadata": {},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"Success: test_pair_parentheses\n"
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]
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}
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],
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"source": [
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"%run -i test_n_pairs_parentheses.py"
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.7.2"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 1
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}
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