Files
interactive-coding-challenges/recursion_dynamic/n_pairs_parentheses/n_pairs_parentheses_solution.ipynb

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6.4 KiB
Python

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"cell_type": "markdown",
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"source": [
"This notebook was prepared by [Rishi Rajasekaran](https://github.com/rishihot55). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges)."
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Solution Notebook"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Problem: Find all valid combinations of n-pairs of parentheses.\n",
"\n",
"* [Constraints](#Constraints)\n",
"* [Test Cases](#Test-Cases)\n",
"* [Algorithm](#Algorithm)\n",
"* [Code](#Code)\n",
"* [Unit Test](#Unit-Test)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Constraints\n",
"\n",
"* Is the input an integer representing the number of pairs?\n",
" * Yes\n",
"* Can we assume the inputs are valid?\n",
" * No\n",
"* Is the output a list of valid combinations?\n",
" * Yes\n",
"* Should the output have duplicates?\n",
" * No\n",
"* Can we assume this fits memory?\n",
" * Yes"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Test Cases\n",
"\n",
"<pre>\n",
"* None -> Exception\n",
"* Negative -> Exception\n",
"* 0 -> []\n",
"* 1 -> ['()']\n",
"* 2 -> ['(())', '()()']\n",
"* 3 -> ['((()))', '(()())', '(())()', '()(())', '()()()']\n",
"</pre>"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Algorithm\n",
"\n",
"Let `l` and `r` denote the number of left and right parentheses remaining at any given point. \n",
"The algorithm makes use of the following conditions applied recursively:\n",
"* Left braces can be inserted any time, as long as we do not exhaust them i.e. `l > 0`.\n",
"* Right braces can be inserted, as long as the number of right braces remaining is greater than the left braces remaining i.e. `r > l`. Violation of the aforementioned condition produces an unbalanced string of parentheses.\n",
"* If both left and right braces have been exhausted i.e. `l = 0 and r = 0`, then the resultant string produced is balanced.\n",
"\n",
"The algorithm can be rephrased as:\n",
"* Base case: `l = 0 and r = 0`\n",
" - Add the string generated to the result set\n",
"* Case 1: `l > 0`\n",
" - Add a left parenthesis to the parentheses string.\n",
" - Recurse (l - 1, r, new_string, result_set)\n",
"* Case 2: `r > l`\n",
" - Add a right parenthesis to the parentheses string.\n",
" - Recurse (l, r - 1, new_string, result_set)\n",
"\n",
"Complexity:\n",
"* Time: `O(4^n/n^(3/2))`, see [Catalan numbers](https://en.wikipedia.org/wiki/Catalan_number#Applications_in_combinatorics) - 1, 1, 2, 5, 14, 42, 132...\n",
"* Space complexity: `O(n)`, due to the implicit call stack storing a maximum of 2n function calls)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Code"
]
},
{
"cell_type": "code",
"execution_count": 1,
"metadata": {},
"outputs": [],
"source": [
"class Parentheses(object):\n",
"\n",
" def find_pair(self, num_pairs):\n",
" if num_pairs is None:\n",
" raise TypeError('num_pairs cannot be None')\n",
" if num_pairs < 0:\n",
" raise ValueError('num_pairs cannot be < 0')\n",
" if not num_pairs:\n",
" return []\n",
" results = []\n",
" curr_results = []\n",
" self._find_pair(num_pairs, num_pairs, curr_results, results)\n",
" return results\n",
"\n",
" def _find_pair(self, nleft, nright, curr_results, results):\n",
" if nleft == 0 and nright == 0:\n",
" results.append(''.join(curr_results))\n",
" else:\n",
" if nleft >= 0:\n",
" self._find_pair(nleft-1, nright, curr_results+['('], results)\n",
" if nright > nleft:\n",
" self._find_pair(nleft, nright-1, curr_results+[')'], results)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Unit Test"
]
},
{
"cell_type": "code",
"execution_count": 2,
"metadata": {},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Overwriting test_n_pairs_parentheses.py\n"
]
}
],
"source": [
"%%writefile test_n_pairs_parentheses.py\n",
"import unittest\n",
"\n",
"\n",
"class TestPairParentheses(unittest.TestCase):\n",
"\n",
" def test_pair_parentheses(self):\n",
" parentheses = Parentheses()\n",
" self.assertRaises(TypeError, parentheses.find_pair, None)\n",
" self.assertRaises(ValueError, parentheses.find_pair, -1)\n",
" self.assertEqual(parentheses.find_pair(0), [])\n",
" self.assertEqual(parentheses.find_pair(1), ['()'])\n",
" self.assertEqual(parentheses.find_pair(2), ['(())',\n",
" '()()'])\n",
" self.assertEqual(parentheses.find_pair(3), ['((()))',\n",
" '(()())',\n",
" '(())()',\n",
" '()(())',\n",
" '()()()'])\n",
" print('Success: test_pair_parentheses')\n",
"\n",
"\n",
"def main():\n",
" test = TestPairParentheses()\n",
" test.test_pair_parentheses()\n",
"\n",
"\n",
"if __name__ == '__main__':\n",
" main()"
]
},
{
"cell_type": "code",
"execution_count": 3,
"metadata": {},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Success: test_pair_parentheses\n"
]
}
],
"source": [
"%run -i test_n_pairs_parentheses.py"
]
}
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