Add Get Absolute Seconds From timedelta Object as a Python TIL

README.md

@@ -10,7 +10,7 @@ working across different projects via [VisualMode](https://www.visualmode.dev/).
 
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-_1784 TILs and counting..._
+_1785 TILs and counting..._
 
 See some of the other learning resources I work on:
 
@@ -1061,6 +1061,7 @@ If you've learned something here, support my efforts writing daily TILs by
 - [Define Sequence Of Tests With Parametrize Decorator](python/define-sequence-of-tests-with-parametrize-decorator.md)
 - [Dunder Methods](python/dunder-methods.md)
 - [Easy Key-Value Aggregates With defaultdict](python/easy-key-value-aggregates-with-defaultdict.md)
+- [Get Absolute Seconds From `timedelta` Object](python/get-absolute-seconds-from-timedelta-object.md)
 - [Install With PIP For Specific Interpreter](python/install-with-pip-for-specific-interpreter.md)
 - [Iterate First N Items From Enumerable](python/iterate-first-n-items-from-enumerable.md)
 - [Iterate Over A Dictionary](python/iterate-over-a-dictionary.md)

python/get-absolute-seconds-from-timedelta-object.md

@@ -0,0 +1,64 @@
+# Get Absolute Seconds From `timedelta` Object
+
+The [`timedelta` object provided by
+`datetime`](https://docs.python.org/3/library/datetime.html#timedelta-objects)
+is a useful built-in concept for representing a duration of time.
+
+```python
+>>> from datetime import timedelta
+>>> diff = timedelta(hours=1, minutes=1, seconds=6)
+>>> diff.seconds
+3666
+```
+
+It is pretty minimal though. There are only a couple things you can inspect
+about it -- `days`, `seconds` (as I did in the snippet above), and
+`microseconds`.
+
+And perhaps that is enough to hint at the issue I recently ran into with it --
+specifically that you can access both `days` and `seconds`.
+
+Let's look at what happens when I have a `timedelta` with more than a day worth
+of seconds.
+
+```python
+>>> diff = timedelta(seconds=(3600 * 24 + 1))
+>>> diff.seconds
+1
+>>> diff.days
+1
+```
+
+I thought `seconds` was going to produce `86401` instead of `1`. The reason is
+because any amount of duration over a day gets converted into the `days` value
+and its the remaining time smaller than a day that is represented by `seconds`.
+
+In my [original implementation of
+`format_time_delta`](https://github.com/jbranchaud/py-vmt/blob/c14eaa56cf5f5c6d0120a95f04f95a6c87443e1c/src/py_vmt/time_helpers.py#L11-L14),
+I was trying to build a relative time string by converting `seconds` into hours,
+minutes, and seconds. That approach falls apart as soon as the delta is greater
+than a day.
+
+```python
+def format_time_delta(diff) -> str:
+    hours, remainder = divmod(diff.seconds, 3600)
+    minutes, remainder = divmod(remainder, 60)
+    seconds = remainder
+
+    # ...
+```
+
+Instead, I needed to reach for [the `total_seconds()` function](https://docs.python.org/3/library/datetime.html#datetime.timedelta.total_seconds).
+This gives "the total number of seconds contained in the duration" and is
+described as equivalent to `diff / timedelta(seconds=1)`.
+
+Here is the [updated version of `format_time_delta`](https://github.com/jbranchaud/py-vmt/blob/ec1875a9d73552f5481e3945ddf522e94d0cc018/src/py_vmt/time_helpers.py?plain=1#L11-L16):
+
+```python
+def format_time_delta(diff: timedelta) -> str:
+    total_seconds = int(diff.total_seconds())
+
+    hours, remainder = divmod(total_seconds, 3600)
+    minutes, remainder = divmod(remainder, 60)
+    seconds = remainder
+```