From 222c1cf8ead37ae2b1488f3393087af4f4114d6f Mon Sep 17 00:00:00 2001
From: jbranchaud <jbranchaud@gmail.com>
Date: Sat, 19 Dec 2015 19:41:11 -0600
Subject: [PATCH] Add Increment All The Numbers as a vim til.

---
 README.md                        |  1 +
 vim/increment-all-the-numbers.md | 34 ++++++++++++++++++++++++++++++++
 2 files changed, 35 insertions(+)
 create mode 100644 vim/increment-all-the-numbers.md

diff --git a/README.md b/README.md
index 3a0bb3b..044b492 100644
--- a/README.md
+++ b/README.md
@@ -288,6 +288,7 @@ smart people at [Hashrocket](http://hashrocket.com/).
 - [Help For Non-Normal Mode Features](vim/help-for-non-normal-mode-features.md)
 - [Horizontal to Vertical and Back Again](vim/horizontal-to-vertical-and-back-again.md)
 - [Incremental Searching](vim/incremental-searching.md)
+- [Increment All The Numbers](vim/increment-all-the-numbers.md)
 - [Interactive Buffer List](vim/interactive-buffer-list.md)
 - [Joining Lines Together](vim/joining-lines-together.md)
 - [Jump To Matching Pair](vim/jump-to-matching-pair.md)
diff --git a/vim/increment-all-the-numbers.md b/vim/increment-all-the-numbers.md
new file mode 100644
index 0000000..2812e69
--- /dev/null
+++ b/vim/increment-all-the-numbers.md
@@ -0,0 +1,34 @@
+# Increment All The Numbers
+
+Vim's substitution feature can be used for more than simple static text
+replacement. Each replacement can be the result of some operation on the
+original text. For instance, what if we'd like to increment all numbers in the
+buffer? We can achieve this by searching for all numbers and then using `\=`
+with `submatch`. Whenever the replacement string of a substitution starts
+with `\=`, the remainder of the string is evaluated as an expression.
+
+Given the following text in our buffer:
+
+```
+1 2 a b c 45 123 1982
+```
+
+We can run the following substitution command:
+
+```
+:%s/\d\+/\=submatch(0)+1/g
+```
+
+This will transform all digits in the buffer resulting in:
+
+```
+2 3 a b c 46 124 1983
+```
+
+Want to decrement all the numbers instead?
+
+```
+:%s/\d\+/\=submatch(0)-1/g
+```
+
+See `:h sub-replace-expression` for more details.