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Add Reference A Capture In The Regex as a sed til

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jbranchaud
2021-04-01 14:43:11 -05:00
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commit b1c022f28f
2 changed files with 34 additions and 1 deletions

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For a steady stream of TILs, [sign up for my newsletter](https://tinyletter.com/jbranchaud).
_1105 TILs and counting..._
_1106 TILs and counting..._
---
@@ -956,6 +956,7 @@ _1105 TILs and counting..._
- [Grab All The Method Names Defined In A Ruby File](sed/grab-all-the-method-names-defined-in-a-ruby-file.md)
- [OSX sed Does Regex A Bit Different](sed/osx-sed-does-regex-a-bit-different.md)
- [Output Only Lines Involved In A Substitution](sed/output-only-lines-involved-in-a-substitution.md)
- [Reference A Capture In The Regex](sed/reference-a-capture-in-the-regex.md)
- [Use An Alternative Delimiter In A Substitution](sed/use-an-alternative-delimiter-in-a-substitution.md)
### Shell

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# Reference A Capture In The Regex
You create a capture group in a `sed` regex by wrapping a pattern in `\(` and
`\)`. Generally, this capture group is referenced in the substitution
expression with `\1`.
The capture references (e.g. `\1`) can also be used in the regex as part of
specifying the match.
For instance, we can do a capture of a single digit followed by a reference to
that capture. That will match any line that has a pair of matching consecutive
digits.
```bash
$ seq 111 | sed -n 's/\([[:digit:]]\)\1/&/p'
11
22
33
44
55
66
77
88
99
100
110
111
```
This also uses `&` in the subex which represents the entire match. The `-n` and
`/p` combination suppresses printing of lines to only those that have
substitutions.