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Add Create A Sequence Of Values With A Step as a unix til
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@@ -10,7 +10,7 @@ pairing with smart people at Hashrocket.
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For a steady stream of TILs, [sign up for my newsletter](https://tinyletter.com/jbranchaud).
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_1130 TILs and counting..._
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_1131 TILs and counting..._
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---
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@@ -1051,6 +1051,7 @@ _1130 TILs and counting..._
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- [Copying Nested Directories With Ditto](unix/copying-nested-directories-with-ditto.md)
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- [Count The Number Of Matches In A Grep](unix/count-the-number-of-matches-in-a-grep.md)
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- [Create A File Descriptor with Process Substitution](unix/create-a-file-descriptor-with-process-substitution.md)
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- [Create A Sequence Of Values With A Step](unix/create-a-sequence-of-values-with-a-step.md)
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- [Curl With Cookies](unix/curl-with-cookies.md)
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- [Curling For Headers](unix/curling-for-headers.md)
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- [Curling With Basic Auth Credentials](unix/curling-with-basic-auth-credentials.md)
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37
unix/create-a-sequence-of-values-with-a-step.md
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37
unix/create-a-sequence-of-values-with-a-step.md
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@@ -0,0 +1,37 @@
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# Create A Sequence Of Values With A Step
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The `seq` utility allows you to output a sequence of values.
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You can start at `1` by default.
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```bash
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$ seq 3
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1
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2
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3
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```
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Or you can specify the starting value.
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```bash
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$ seq 10 13
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10
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11
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12
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13
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```
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Adding a third argument in between those two will specify the step value that
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should be taken to get from one to the other.
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```bash
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$ seq 6 3 15
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6
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9
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12
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15
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```
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That sequence starts at 6 and goes to 15 with a step value of 3.
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See `man seq` for more details.
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