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Add Counting Records With Ecto as an elixir til
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@@ -7,7 +7,7 @@ variety of languages and technologies. These are things that don't really
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warrant a full blog post. These are mostly things I learn by pairing with
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smart people at [Hashrocket](http://hashrocket.com/).
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_500 TILs and counting..._
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_501 TILs and counting..._
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---
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@@ -87,6 +87,7 @@ _500 TILs and counting..._
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- [Assert An Exception Is Raised](elixir/assert-an-exception-is-raised.md)
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- [Binary Representation Of A String](elixir/binary-representation-of-a-string.md)
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- [Check For A Substring Match](elixir/check-for-a-substring-match.md)
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- [Counting Records With Ecto](elixir/counting-records-with-ecto.md)
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- [Create A Date With The Date Sigil](elixir/create-a-date-with-the-date-sigil.md)
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- [Creating Indexes With Ecto](elixir/creating-indexes-with-ecto.md)
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- [Determine The Latest Release Of A Hex Package](elixir/determine-the-latest-release-of-a-hex-package.md)
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40
elixir/counting-records-with-ecto.md
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40
elixir/counting-records-with-ecto.md
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@@ -0,0 +1,40 @@
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# Counting Records With Ecto
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Sometimes you want to know how many records there are in a table. Ecto gives
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us a couple ways to approach this.
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We can use the
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[`count\1`](https://hexdocs.pm/ecto/Ecto.Query.API.html#count/1) function
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that the Ecto query API provides.
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```elixir
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> Repo.one(from p in "people", select: count(p.id))
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16:09:52.759 [debug] QUERY OK source="people" db=1.6ms
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SELECT count(p0."id") FROM "people" AS p0 []
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168
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```
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Alternatively, we can use the
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[`fragment/1`](https://hexdocs.pm/ecto/Ecto.Query.API.html#fragment/1)
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function to use PostgreSQL's `count` function.
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```elixir
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> Repo.one(from p in "people", select: fragment("count(*)"))
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16:11:19.818 [debug] QUERY OK source="people" db=1.5ms
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SELECT count(*) FROM "people" AS p0 []
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168
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```
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Lastly, `Ecto.Repo` has the
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[`aggregate/4`](https://hexdocs.pm/ecto/Ecto.Repo.html#c:aggregate/4)
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function which provides a `:count` option.
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```elixir
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> Repo.aggregate(from(p in "people"), :count, :id)
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16:11:23.786 [debug] QUERY OK source="people" db=1.7ms
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SELECT count(p0."id") FROM "people" AS p0 []
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168
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```
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