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Add OSX sed Does Regex A Bit Different as a sed til

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jbranchaud
2021-03-24 09:31:49 -05:00
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commit b27b44d637
2 changed files with 34 additions and 1 deletions

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For a steady stream of TILs, [sign up for my newsletter](https://tinyletter.com/jbranchaud).
_1095 TILs and counting..._
_1096 TILs and counting..._
---
@@ -948,6 +948,7 @@ _1095 TILs and counting..._
- [Apply Multiple Substitutions To The Input](sed/apply-multiple-substitutions-to-the-input.md)
- [Extract Value From Command Output With Sed](sed/extract-value-from-command-output-with-sed.md)
- [Grab All The Method Names Defined In A Ruby File](sed/grab-all-the-method-names-defined-in-a-ruby-file.md)
- [OSX sed Does Regex A Bit Different](sed/osx-sed-does-regex-a-bit-different.md)
- [Output Only Lines Involved In A Substitution](sed/output-only-lines-involved-in-a-substitution.md)
- [Use An Alternative Delimiter In A Substitution](sed/use-an-alternative-delimiter-in-a-substitution.md)

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# OSX sed Does Regex A Bit Different
With GNU sed, `\+`, `\?`, `\(...\)` and friends are considered extended regex
characters. You can use them directly with the preceding backslashes. Or you
can include the `-r` flag to turn on extended regex and use them without.
```bash
$ echo '11+1 = 12' | sed 's/1+/3/'
131 = 12
$ echo '11+1 = 12' | sed -r 's/1+/3/'
3+1 = 12
```
With OSX sed, `\+`, `\?`, and `\|` are not interpreted as part of the basic
regex. To use them at all you need to include `-E` to turn on extended regex.
The capture characters (`\(...\)`) are available with basic regex.
```bash
# Basic, always treated as literal +
$ echo '11+1 = 12' | sed 's/1+/3/'
131 = 12
$ echo '11+1 = 12' | sed 's/1\+/3/'
131 = 12
# Extended, + is now a meta-character
$ echo '11+1 = 12' | sed -E 's/1+/3/'
3+1 = 12
$ echo '11+1 = 12' | sed -E 's/1\+/3/'
131 = 12
```
[source](https://unix.stackexchange.com/a/131940/5916)