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53 lines
2.0 KiB
Markdown
53 lines
2.0 KiB
Markdown
# Strictly Separate Positional And Keyword Arguments
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Typically when I define a function with arguments in Python, I can choose pass
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the arguments to that function as positional or keyword arguments. I can even
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mix and match as long as all positional arguments come before all keyword
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arguments.
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But what if I want to enforce a strict boundary between what arguments are
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positional and what arguments are keyword?
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By combining the _positional-only marker_ (`/`) and _keyword-only marker_ (`*`),
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I can get exactly that effect.
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Here I have defined a `connect` function that takes `host` and `port` arguments.
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Because both appear before the `/` marker, they must be passed as positional. I
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also have a `timeout` argument with a default. Because `timeout` comes after the
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`*` marker, it must be passed as a keyword argument.
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```python
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def connect(host, port, /, *, timeout=30):
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print(f"Connecting to #{host}:#{port}")
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print(f" Timeout: {timeout}s")
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# ...
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```
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Let's see it in action.
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```python
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>>> connect("localhost", 3000, timeout=20)
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Connecting to #localhost:#3000
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Timeout: 20s
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>>> connect(host="localhost", port=4000)
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Traceback (most recent call last):
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File "/Users/lastword/dev/misc/python-experiments/arguments.py", line 37, in <module>
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connect(host="localhost", port=4000)
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TypeError: connect() got some positional-only arguments passed as keyword arguments: 'host, port'
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```
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This second attempt of calling `connect` with `host` and `port` as keyword
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arguments presents as a runtime `TypeError` because they were expected as
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"positional-only arguments".
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In my editor that line also presents with two static typing errors `call-arg:
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Unexpected keyword argument "port" for "connect"` (and the equivalent for
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`host`).
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Note: I did some additional reading just now in [Python in a Nutshell, 4th
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Edition](https://www.oreilly.com/library/view/python-in-a/9781098113544/) and I
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see that it is more appropriate to call them _Named Arguments_ instead of
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_Keyword Arguments_.
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