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OSX sed Does Regex A Bit Different
With GNU sed, \+, \?, \(...\) and friends are considered extended regex
characters. You can use them directly with the preceding backslashes. Or you
can include the -r flag to turn on extended regex and use them without.
$ echo '11+1 = 12' | sed 's/1+/3/'
131 = 12
$ echo '11+1 = 12' | sed -r 's/1+/3/'
3+1 = 12
With OSX sed, \+, \?, and \| are not interpreted as part of the basic
regex. To use them at all you need to include -E to turn on extended regex.
The capture characters (\(...\)) are available with basic regex.
# Basic, always treated as literal +
$ echo '11+1 = 12' | sed 's/1+/3/'
131 = 12
$ echo '11+1 = 12' | sed 's/1\+/3/'
131 = 12
# Extended, + is now a meta-character
$ echo '11+1 = 12' | sed -E 's/1+/3/'
3+1 = 12
$ echo '11+1 = 12' | sed -E 's/1\+/3/'
131 = 12